Kenwood Pool Service entered the industry of Services (Unclassified) in 2010 and has grown to employ 1 to 4 people, generating an annual revenue of $100.000 to $499.999. The NAICS classifies this business under the code 2362204, which describes it as a Services (Unclassified). For further clarification, the SIC classifies this business under the code 8999 and described it as a Services (Unclassified). The business provides service to the B2B market.
To acquire more information, please contact Robert Russell, Owner by calling (215) 547-7175 during business hours. You can also write to the business’ Single Location at 1401 Elkins Avenue, Levittown, Pennsylvania PA 19057. You can also visit the company’s website at . View this business’ social media profiles on Twitter or on Facebbok .
| Company: | Kenwood Pool Service |
| Representative: | Robert Russell, Owner |
| Place of Business: | 1401 Elkins Avenue, Levittown, PA 19057 |
| Contact Number: | (215) 547-7175 |
| Type of Service: | Services (Unclassified) |
| SIC Number: | 8999 |
| NAICS Number: | 2362204 |
| Locality: | Single Location |
| Market Type: | B2B (Business to Business) |
| Began: | 2010 |
| Income/Year: | $100.000 to $499.999 |
| Laborers: | 1 to 4 |
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Kenwood Pool Service is a company operating from Bucks, Pennsylvania providing professional Services (Unclassified) and relevant B2B variables. It was founded in 2010 and registered with the SIC code 8999 as Services (Unclassified), and with the NAICS code 2362204 as Services (Unclassified).
With a current employee count of 1 to 4, Kenwood Pool Service has gone to report making $100.000 to $499.999 per annum on its journey towards growth. This company invites you to contact its representative Robert Russell, Owner at (215) 547-7175 for related queries, or to locate its Single Location using the coordinates 40.130703,-74.830005.
The Single Location can also be found at the street address 1401 Elkins Avenue in Levittown, Pennsylvania 19057 and can be engaged online through the company website at , the company Twitter , and Facebook page .